сверхшпион in All languages combined

IPA: ˌsvʲerxʂpʲɪˈon [Show additional information ▼] [Hide additional information ▲]

Etymology: Происходит от ?? Forms: сверхшпио́н [nominative, singular], сверхшпио́ны [nominative, plural], сверхшпио́на [genitive, singular], сверхшпио́нов [genitive, plural], сверхшпио́ну [dative, singular], сверхшпио́нам [dative, plural], сверхшпио́на [accusative, singular], сверхшпио́нов [accusative, plural], сверхшпио́ном [instrumental, singular], сверхшпио́нами [instrumental, plural], сверхшпио́не [prepositional, singular], сверхшпио́нах [prepositional, plural]

[Show JSON for postprocessed kaikki.org data shown on this page ▼] [Hide JSON for postprocessed kaikki.org data shown on this page ▲]

{
  "categories": [
    {
      "kind": "other",
      "name": "Мужской род/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нет сведений о составе слова/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Нужна этимология",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Одушевлённые/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские лексемы",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русские существительные, склонение 1a",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Русский язык",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Слова из 10 букв/ru",
      "parents": [],
      "source": "w"
    },
    {
      "kind": "other",
      "name": "Требуется категоризация/ru",
      "parents": [],
      "source": "w"
    }
  ],
  "etymology_text": "Происходит от ??",
  "forms": [
    {
      "form": "сверхшпио́н",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́ны",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́на",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́ну",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́на",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нов",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́ном",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́не",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "о шпионе высокого класса"
      ],
      "id": "ru-сверхшпион-ru-noun-UnHYJES1"
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsvʲerxʂpʲɪˈon"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "супершпион"
    }
  ],
  "tags": [
    "animate",
    "declension-2",
    "masculine"
  ],
  "word": "сверхшпион"
}

[Show JSON for raw wiktextract data ▼] [Hide JSON for raw wiktextract data ▲]

{
  "categories": [
    "Мужской род/ru",
    "Нет сведений о составе слова/ru",
    "Нужна этимология",
    "Одушевлённые/ru",
    "Русские лексемы",
    "Русские существительные",
    "Русские существительные, склонение 1a",
    "Русский язык",
    "Слова из 10 букв/ru",
    "Требуется категоризация/ru"
  ],
  "etymology_text": "Происходит от ??",
  "forms": [
    {
      "form": "сверхшпио́н",
      "tags": [
        "nominative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́ны",
      "tags": [
        "nominative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́на",
      "tags": [
        "genitive",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нов",
      "tags": [
        "genitive",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́ну",
      "tags": [
        "dative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нам",
      "tags": [
        "dative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́на",
      "tags": [
        "accusative",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нов",
      "tags": [
        "accusative",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́ном",
      "tags": [
        "instrumental",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нами",
      "tags": [
        "instrumental",
        "plural"
      ]
    },
    {
      "form": "сверхшпио́не",
      "tags": [
        "prepositional",
        "singular"
      ]
    },
    {
      "form": "сверхшпио́нах",
      "tags": [
        "prepositional",
        "plural"
      ]
    }
  ],
  "lang": "Русский",
  "lang_code": "ru",
  "pos": "noun",
  "senses": [
    {
      "glosses": [
        "о шпионе высокого класса"
      ]
    }
  ],
  "sounds": [
    {
      "ipa": "ˌsvʲerxʂpʲɪˈon"
    }
  ],
  "synonyms": [
    {
      "sense_index": 1,
      "word": "супершпион"
    }
  ],
  "tags": [
    "animate",
    "declension-2",
    "masculine"
  ],
  "word": "сверхшпион"
}

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This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-10-06 from the ruwiktionary dump dated 2024-10-02 using wiktextract (9f93753 and c1a3a36). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.

If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.

"сверхшпион" meaning in All languages combined

Noun [Русский]